Using the Table: P(sum = 7)
From the two-dice table (Lesson 1):
- Highlighted cells: (1,6), (2,5), (3,4), (4,3), (5,2), (6,1) — 6 favorable
Using the Table to Find P(sum ≥ 10)
Count pairs where sum = 10, 11, or 12:
- Sum = 10: (4,6), (5,5), (6,4) → 3 pairs
- Sum = 11: (5,6), (6,5) → 2 pairs
- Sum = 12: (6,6) → 1 pair
P(at least one 3): Avoiding Double-Count
Die 1 = 3 OR Die 2 = 3 — but (3,3) is in both row 3 and column 3.
- Row 3: 6 outcomes; Column 3: 6 outcomes; overlap: (3,3) counted twice
Guided Practice: P(doubles) from Table
Using the two-dice table:
- Doubles = both dice show the same value
- Locate all cells where Die 1 = Die 2
Count the favorable outcomes and write
P(doubles) Answer from the Table
Favorable: (1,1), (2,2), (3,3), (4,4), (5,5), (6,6) → 6 outcomes
Using the Tree: Three Coin Probabilities
From the 3-coin tree: {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT} — 8 paths.
| Event | Favorable paths | Probability |
|---|---|---|
| Exactly 2 heads | HHT, HTH, THH | 3/8 |
| All same | HHH, TTT | 2/8 = 1/4 |
Check-In: Coin Probability from Tree
From the 3-coin tree:
What is P(first coin = H AND third coin = T)?
List the favorable paths, then compute the probability.
Check-In Answer: First H and Third T
Favorable paths where flip 1 = H and flip 3 = T:
- HHT ✓ (H, H, T)
- HTT ✓ (H, T, T)
Count: 2 favorable paths
When Sample Spaces Are Too Large
The two-dice table works because 36 outcomes is manageable.
What if we needed: "Probability that at least one of 5 friends has a birthday on a weekend"?
- Each person: 7 possible birthday days → $7^5 = $ 16,807 outcomes
Enumerating is impractical. Simulation gives an approximation.
Simulation Design: Four Required Decisions
Every simulation needs four design decisions:
- Random mechanism — what mimics the real probability?
- One trial — what counts as one repetition?
- Success — what outcome counts as the event?
- Repetitions — how many trials to run?
Applying the Template: Weekend Birthday
Event: At least one of 5 friends has a birthday on a weekend.
Use random digits 1–7: {1, 2} = weekend; {3, 4, 5, 6, 7} = weekday.
Running the Simulation: Class Pooling
Simpler simulation: P(both flips are heads) = P(HH) — theoretical = 1/4 = 0.25
Mechanism: Roll a die — 1, 2, 3 = Heads; 4, 5, 6 = Tails. Two rolls = one trial.
Class run: Each student does 4 trials. Pool all results.
Compare class estimate to 0.25.
Practice: Design Your Own Simulation
3-child family. Estimate
- Mechanism: Coin — Heads = girl, Tails = boy
- Trial: Flip 3 times
- Success: At least 2 heads
- Repetitions: 30 trials
Record results and compute your estimate.
Compare Simulation to Theory: 3-Child Family
Theoretical calculation: List all outcomes from the 3-coin tree:
Outcomes with ≥ 2 girls: GGG, GGB, GBG, BGG → 4 out of 8
How close was your simulation estimate?
Lesson 2 Summary and Misconception Review
— complete sample space required- Simulation estimates probability when enumeration is impractical
Watch out:
- Stage order fixed; HT ≠ TH
- Total =
; count tree leaves not branches - "At least N" includes N and beyond
- Simulation results vary — not an error
Compound Events: Complete Lesson Summary
This two-lesson unit covered:
- Defining compound events and the combined sample space
- Building sample spaces: organized lists, tables, tree diagrams
- Computing
by counting and dividing - Designing and interpreting simulations
Next: High school probability builds on this with counting principles and formal probability rules.
Click to begin the narrated lesson
Find probabilities of compound events using organized lists, tables, tree diagrams, and simulation