Using the Table: P(sum = 7)
From the two-dice table (Lesson 1):
- Highlighted cells: (1,6), (2,5), (3,4), (4,3), (5,2), (6,1) — 6 favorable
Using the Table to Find P(sum ≥ 10)
Count pairs where sum = 10, 11, or 12:
- Sum = 10: (4,6), (5,5), (6,4) → 3 pairs
- Sum = 11: (5,6), (6,5) → 2 pairs
- Sum = 12: (6,6) → 1 pair
P(at least one 3): Avoiding Double-Count
Die 1 = 3 OR Die 2 = 3 — but (3,3) is in both row 3 and column 3.
- Row 3: 6 outcomes; Column 3: 6 outcomes; overlap: (3,3) counted twice
Guided Practice: P(doubles) from Table
Using the two-dice table:
- Doubles = both dice show the same value
- Locate all cells where Die 1 = Die 2
Count the favorable outcomes and write
P(doubles) Answer from the Table
Favorable: (1,1), (2,2), (3,3), (4,4), (5,5), (6,6) → 6 outcomes
Using the Tree: Three Coin Probabilities
From the 3-coin tree: {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT} — 8 paths.
| Event | Favorable paths | Probability |
|---|---|---|
| Exactly 2 heads | HHT, HTH, THH | 3/8 |
| All same | HHH, TTT | 2/8 = 1/4 |
Check-In: Coin Probability from Tree
From the 3-coin tree:
What is P(first coin = H AND third coin = T)?
List the favorable paths, then compute the probability.
Check-In Answer: First H and Third T
Favorable paths where flip 1 = H and flip 3 = T:
- HHT ✓ (H, H, T)
- HTT ✓ (H, T, T)
Count: 2 favorable paths
When Sample Spaces Are Too Large
The two-dice table works because 36 outcomes is manageable.
What if we needed: "Probability that at least one of 5 friends has a birthday on a weekend"?
- Each person: 7 possible birthday days → $7^5 = $ 16,807 outcomes
Enumerating is impractical. Simulation gives an approximation.
Simulation Design: Four Required Decisions
Every simulation needs four design decisions:
- Random mechanism — what mimics the real probability?
- One trial — what counts as one repetition?
- Success — what outcome counts as the event?
- Repetitions — how many trials to run?
Applying the Template: Weekend Birthday
Event: At least one of 5 friends has a birthday on a weekend.
Use random digits 1–7: {1, 2} = weekend; {3, 4, 5, 6, 7} = weekday.
Running the Simulation: Class Pooling
Simpler simulation: P(both flips are heads) = P(HH) — theoretical = 1/4 = 0.25
Mechanism: Roll a die — 1, 2, 3 = Heads; 4, 5, 6 = Tails. Two rolls = one trial.
Class run: Each student does 4 trials. Pool all results.
Compare class estimate to 0.25.
Practice: Design Your Own Simulation
3-child family. Estimate
- Mechanism: Coin — Heads = girl, Tails = boy
- Trial: Flip 3 times
- Success: At least 2 heads
- Repetitions: 30 trials
Record results and compute your estimate.
Compare Simulation to Theory: 3-Child Family
Theoretical calculation: List all outcomes from the 3-coin tree:
Outcomes with ≥ 2 girls: GGG, GGB, GBG, BGG → 4 out of 8
How close was your simulation estimate?
Lesson 2 Summary and Misconception Review
— complete sample space required- Simulation estimates probability when enumeration is impractical
Watch out:
- Stage order fixed; HT ≠ TH
- Total =
; count tree leaves not branches - "At least N" includes N and beyond
- Simulation results vary — not an error
Compound Events: Complete Lesson Summary
This two-lesson unit covered:
- Defining compound events and the combined sample space
- Building sample spaces: organized lists, tables, tree diagrams
- Computing
by counting and dividing - Designing and interpreting simulations
Next: High school probability builds on this with counting principles and formal probability rules.