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Parallelogram Theorems | Lesson 1 of 2

Prove Theorems About Parallelograms

Lesson 1 of 2

In this lesson:

  • Prove opposite sides and angles of a parallelogram are congruent
  • Prove the diagonals of a parallelogram bisect each other
  • Prove the converse: bisecting diagonals imply a parallelogram
Grade 9 Geometry | HSG.CO.C.11
Parallelogram Theorems | Lesson 1 of 2

Parallelogram Theorems: Three Goals for Today

By the end of this lesson, you should be able to:

  1. Prove opposite sides of a parallelogram are congruent (ASA + alternate interior angles)
  2. Prove opposite angles are congruent (CPCTC + co-interior angles)
  3. Prove diagonals bisect each other — and the converse
Grade 9 Geometry | HSG.CO.C.11
Parallelogram Theorems | Lesson 1 of 2

What Can Parallel Lines Tell Us?

Today we combine three tools you already know:

  • Alternate interior angles: parallel lines → congruent angles
  • ASA congruence: two angles + included side → triangles congruent
  • CPCTC: corresponding parts of congruent triangles are congruent

Question: Two pairs of parallel sides — what follows?

Grade 9 Geometry | HSG.CO.C.11
Parallelogram Theorems | Lesson 1 of 2

Setting Up the Parallelogram Proof

Parallelogram ABCD with vertices labeled, diagonal AC drawn, AB∥DC and AD∥BC marked

Grade 9 Geometry | HSG.CO.C.11
Parallelogram Theorems | Lesson 1 of 2

The Diagonal Splits Into Two Triangles

  • divides into and ; (reflexive)

Since : (alt. interior angles)

Since : (alt. interior angles)

Grade 9 Geometry | HSG.CO.C.11
Parallelogram Theorems | Lesson 1 of 2

Alternate Interior Angles on Diagonal AC

Parallelogram ABCD with diagonal AC, angle BAC and angle DCA marked in teal, angle BCA and angle DAC marked in red

  • Teal angles: (from )
  • Red angles: (from )
  • Shared side: (reflexive)
Grade 9 Geometry | HSG.CO.C.11
Parallelogram Theorems | Lesson 1 of 2

ASA Proof: Opposite Sides Congruent

Given: is a parallelogram. Prove: and .

Statement Reason
is a parallelogram Given
Definition of parallelogram
Alternate interior angles (, transversal )
Alternate interior angles (, transversal )
Reflexive property
ASA
and CPCTC
Grade 9 Geometry | HSG.CO.C.11
Parallelogram Theorems | Lesson 1 of 2

Result: Opposite Sides Are Congruent

  • The diagonal divides the parallelogram into two congruent triangles
  • This result becomes a building block for every subsequent proof

Strategy: One diagonal → two triangles → alternate interior angles → ASA → CPCTC

Grade 9 Geometry | HSG.CO.C.11
Parallelogram Theorems | Lesson 1 of 2

Check: Apply the Opposite Sides Theorem

In parallelogram , if and , find and .

Name the theorem before computing, then find the values.

Grade 9 Geometry | HSG.CO.C.11
Parallelogram Theorems | Lesson 1 of 2

Answer: Opposite Sides Are Congruent

By the Opposite Sides Theorem: opposite sides are congruent.

  • No calculation needed — the theorem applies directly
  • Knowing two adjacent sides tells you all four sides
Grade 9 Geometry | HSG.CO.C.11
Parallelogram Theorems | Lesson 1 of 2

Proving Opposite Angles Are Congruent

Approach 1 (congruent triangles):

  • by CPCTC

Approach 2 (co-interior angles):

Grade 9 Geometry | HSG.CO.C.11
Parallelogram Theorems | Lesson 1 of 2

Consecutive Angles in a Parallelogram Are Supplementary

If Then
opposite angles congruent
consecutive angles supplementary
consecutive angles supplementary
Grade 9 Geometry | HSG.CO.C.11
Parallelogram Theorems | Lesson 1 of 2

Check: Find All Four Angle Measures

In parallelogram , . Find , , and .

Use the relationship table — name each reason before writing the value.

Grade 9 Geometry | HSG.CO.C.11
Parallelogram Theorems | Lesson 1 of 2

Answer: Using Opposite and Supplementary Angles

  • (opposite angles congruent)
  • and (consecutive angles supplementary)

⚠️ Watch out: One pair of congruent sides alone ≠ parallelogram.

Grade 9 Geometry | HSG.CO.C.11
Parallelogram Theorems | Lesson 1 of 2

Diagonals: Setting Up the Next Proof

Now draw both diagonals of parallelogram . They intersect at point .

Observation: Measure , , , . What do you find?

The diagonals appear to bisect each other. Our job: prove it.

Grade 9 Geometry | HSG.CO.C.11
Parallelogram Theorems | Lesson 1 of 2

Both Diagonals Intersecting at E

Parallelogram ABCD with both diagonals AC and BD drawn, intersection point E labeled, AE, CE, BE, DE segments labeled

Forward direction: Given is a parallelogram → prove and

Grade 9 Geometry | HSG.CO.C.11
Parallelogram Theorems | Lesson 1 of 2

Forward Proof: Diagonals Bisect Each Other

Given: is a parallelogram. Diagonals intersect at .
Prove: and .

Statement Reason
is a parallelogram Given
Definition of parallelogram
Alternate interior angles (, transversal )
Alternate interior angles (, transversal )
Opposite sides of a parallelogram are congruent (proved above)
ASA
and CPCTC
Grade 9 Geometry | HSG.CO.C.11
Parallelogram Theorems | Lesson 1 of 2

Understanding What Bisect Means Here

  • : is the midpoint of diagonal
  • : is the midpoint of diagonal

⚠️ Watch out: means the diagonal is cut in half — not that equals a side. Half-diagonals ≠ sides.

Grade 9 Geometry | HSG.CO.C.11
Parallelogram Theorems | Lesson 1 of 2

Converse: If Diagonals Bisect → Parallelogram

Given: Quadrilateral with diagonals intersecting at , where and .
Prove: is a parallelogram.

Key tool: vertical angles at

Statement Reason
, Given
Vertical angles
SAS (, , )
CPCTC
Converse of alternate interior angles (transversal )
Grade 9 Geometry | HSG.CO.C.11
Parallelogram Theorems | Lesson 1 of 2

Converse Proof: Second Pair of Parallel Lines

Continuing from the previous slide:

Statement Reason
Vertical angles
SAS (, , )
CPCTC
Converse of alternate interior angles (transversal )
is a parallelogram Both pairs of opposite sides are parallel (definition)
Grade 9 Geometry | HSG.CO.C.11
Parallelogram Theorems | Lesson 1 of 2

Quick Check: Converse in Action

Quadrilateral has diagonals and that intersect at midpoint , with and .

Is a parallelogram? Which theorem justifies your answer?

Identify the theorem, then state the conclusion.

Grade 9 Geometry | HSG.CO.C.11
Parallelogram Theorems | Lesson 1 of 2

Answer: Diagonals Bisecting Proves Parallelogram

Yes — is a parallelogram.

bisects . bisects . Both diagonals are bisected at .

By the converse: bisecting diagonals → parallelogram. ✓

Grade 9 Geometry | HSG.CO.C.11
Parallelogram Theorems | Lesson 1 of 2

Midpoint Test: Proving Parallelogram by Coordinates

Vertices: , , , .

Same midpoint → diagonals bisect each other → parallelogram

Grade 9 Geometry | HSG.CO.C.11
Parallelogram Theorems | Lesson 1 of 2

Key Takeaways — Deck 1

Opposite sides congruent (ASA + CPCTC)

Opposite angles congruent; consecutive angles supplementary

Diagonals bisect each other (forward: ASA; converse: SAS + vertical angles)

⚠️ One pair of congruent sides is not enough — need both

⚠️ Half-diagonals ≠ sides; each converse needs its own proof

Grade 9 Geometry | HSG.CO.C.11
Parallelogram Theorems | Lesson 1 of 2

What Comes Next: Deck 2

In Deck 2 — Rectangles and Special Parallelograms:

  • Rectangles: additional property of congruent diagonals — forward (SAS) and converse (SSS)
  • Classification hierarchy: rectangle, rhombus, square — which properties belong where?
  • Five methods to prove a quadrilateral is a parallelogram
Grade 9 Geometry | HSG.CO.C.11