Geometric Methods for Design | Lesson 2 of 2

Constraint Design and Grid Systems

Deck 2 of 2: Feasible Regions and Ratio-Based Design

Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 2 of 2

Learning Objectives: Deck 2 Focus

Continuing from Deck 1:

  1. Apply the modeling cycle to constraint-based design problems
  2. Analyze design trade-offs — improving one property affects another
  3. Solve design problems involving packaging and typographic grid systems

Also revisiting: translating verbal constraints to geometric inequalities (LO 1)

Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 2 of 2

Every Design Exists Within Limits

Design problems always start with constraints:

  • Shipping: cm
  • Facility: tank through 3 m door → m
  • Shelf: , , cm

Constraint translation: verbal requirement → inequality → feasible region

Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 2 of 2

Translating Verbal Constraints into Geometric Inequalities

Verbal requirement Geometric inequality
Package fits shipping limit cm
Tank fits through doorway m → m
Box fits on a shelf , , cm
Volume must meet capacity cm³
Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 2 of 2

Shipping Box: Maximize Volume Under a Sum Constraint

Problem: A shipping company limits packages to cm.
Design a rectangular box with maximum volume.

Strategy: Use the equality case () and ask: how should the 150 cm be divided?

Volume
60 50 40 120,000 cm³
70 40 40 112,000 cm³
50 50 50 125,000 cm³ ← maximum

A cube maximizes volume when the dimension sum is fixed.

Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 2 of 2

A Cube Maximizes Volume for Any Fixed Sum

Equal dimensions maximize volume for a fixed dimension sum:

Compare: cm³ — lower.

Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 2 of 2

Water Tank: Both Constraints Are Active

Problem: Cylinder must fit in 3 m × 4 m space. Maximize .

Constraints: m, m

Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 2 of 2

Check-In: Designing a Box for a Shelf

A box must hold ≥ 5,000 cm³ and fit on a shelf 30 × 50 × 25 cm.

Give one valid set of dimensions () and verify each constraint.

Try before advancing.

Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 2 of 2

Answer: One Valid Design (Many Are Correct)

One valid solution: cm, cm, cm

Constraints: Depth 20 ≤ 30 ✓ · Width 25 ≤ 50 ✓ · Height 10 ≤ 25 ✓

Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 2 of 2

Packaging: Counting Cans in a Shipping Box

Can: ∅ 8 cm, h = 12 cm. Box: 48 × 40 × 36 cm.

Top-view grid of cylindrical cans packed in rectangular box, systematic row-column count

  • 48 ÷ 8 = 6 per row; 40 ÷ 8 = 5 rows; 36 ÷ 12 = 3 layers

Total: cans

Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 2 of 2

Packing Efficiency: What Fraction Is Wasted?

Box volume: cm³

Can volume: cm³

22% wasted — circles never tile a plane perfectly.

Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 2 of 2

Feasible Region and the Optimization Mindset

  • Feasible region: all designs satisfying every constraint
  • Optimal design: the best point in the feasible region

Two types of optima:

  • Boundary — objective is monotone; push dimensions to their limits
  • Interior — competing effects balance; use table search or calculus
Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 2 of 2

Geometry Shapes Two-Dimensional Design Too

Geometry doesn't just shape containers — it shapes communication.

Every page, website, and poster uses a geometric grid:

  • Column widths calculated from page dimensions
  • Margins set in proportional ratios
  • Layout proportions based on classical geometric relationships
Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 2 of 2

Column Grid Systems: The Formula

columns, each width , separated by gutters of width :

Solving for column width:

Note: columns → gutters between them, not .

Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 2 of 2

Column Grid: Visual Layout with Four Columns

Page diagram showing 4 columns with labeled gutter widths and total page width

Four columns, three gutters — gutters always separate columns.

Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 2 of 2

Web Grid: Calculating Column Width

960 px wide, 12 columns, 20 px gutters — find each column width.

11 gutters between 12 columns:

Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 2 of 2

Book Page Margins: Ratio-Based Design

Problem: A 6 in × 9 in book with margin ratios 2:3:4:6 (inner🔝outer:bottom).
Given inner margin = 0.75 in, find all four margins.

Margin Ratio Value Text block
Inner 2 0.75 in Width: = 3.75 in
Top 3 1.125 in Height: = 5.625 in
Outer 4 1.5 in
Bottom 6 2.25 in
Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 2 of 2

Check-In: Computing the Poster Column Width

Poster: 24 in wide, 6 columns, 0.5 in gutters. Find each column width.

  1. How many gutters?
  2. What is total gutter space?
  3. Remaining space for columns?
  4. Each column width?

Work through the four steps before advancing.

Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 2 of 2

Answer: Poster Column Width Calculation

6 columns, 0.5 in gutters, 24 in wide

Step Calculation Result
Gutters gutters 5
Gutter space 2.5 in
Column space 21.5 in
Column width 3.58 in

Confirm:

Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 2 of 2

Golden Ratio: Dividing a Width Proportionally

Golden ratio: divides a 30 in poster in ratio (image : text).

Let text ; image :

  • Text area: ≈ 11.46 in
  • Image area: ≈ 18.54 in
Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 2 of 2

Misconception: Design Has No Unique Right Answer

Common error: Any feasible design is declared "correct" — but feasible designs are not all equal.

Reality:

  • Design problems have a feasible region and an objective
  • The objective determines which feasible design is best
  • Step 1: find a valid answer. Step 2: compare by objective.
Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 2 of 2

Key Takeaways: Decks 1 and 2

Modeling cycle applies to all design problems

Constraints define feasible region; optimization picks the best

Grid formula: W = n·c + (n−1)·g

⚠️ Watch out:

  • Constraint (fixed) vs. objective (minimize)
  • Unconstrained optimum may be infeasible
  • Find the best design, not just any valid one
Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 2 of 2

This Completes the Modeling with Geometry Cluster

HSG.MG.A.3 pulls together everything from the cluster:

Standard What it provides
HSG.MG.A.1 Geometric shapes as models for real objects
HSG.MG.A.2 Density connects geometric measurement to physical properties
HSG.MG.A.3 Geometric methods for design — constraints, optimization, ratios

What's next:

  • In calculus, these optimization ideas are formalized using derivatives
  • In engineering and architecture, this modeling cycle drives real design decisions
  • In computer science, constraint satisfaction and optimization algorithms extend these ideas
Grade 10 Geometry | HSG.MG.A.3

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Apply geometry to design problems