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Geometric Methods for Design | Lesson 1 of 2

Geometric Methods for Design Problems

Deck 1 of 2: Modeling Cycle and Optimization

Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 1 of 2

Learning Objectives for This Lesson

By the end of this lesson, you will be able to:

  1. Translate requirements into geometric equations
  2. Apply the five-step modeling cycle
  3. Solve material optimization for cylinders and boxes
  4. Check whether a mathematical solution is practical
  5. Explain why real designs deviate from optimal models
Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 1 of 2

You Are Starting a Candle Company

Design a candle with three requirements:

  • Hold exactly 250 mL of wax (250 cm³)
  • Fit in a 12 cm cube gift box
  • Minimize wax usage (cost)

Question: What shape? What dimensions? How do you decide?

Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 1 of 2

The Five Steps of the Modeling Cycle

  1. Define — What are we designing? What must it do?
  2. Constrain — What limits exist? (size, cost, weight)
  3. Set Up — Write constraints and objective as equations
  4. Explore — Try values; compute objective for each
  5. Interpret — Does the solution make sense practically?
Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 1 of 2

Candle Problem: Steps 1 and 2

Step 1 — Define: Cylindrical candle, cm³

Step 2 — Constrain:

  • Fits in 12 cm cube: cm and cm
  • Objective: minimize surface area (wax cost)

Constraints define what is possible. The objective picks the best.

Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 1 of 2

Candle Problem: Step Three — Set Up

Volume links and — two variables become one:

Once is chosen, is determined.
SA becomes a function of alone.

Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 1 of 2

Candle Problem: Step Four — Explore

SA = 2πr² + 2πrh — substitute constraint for :

(cm) (cm) SA (cm²) Fits box?
3 8.84 222
4 4.97 226
5 3.18 257
6 2.21 309

Minimum SA near cm within constraints.

Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 1 of 2

Candle Problem: Step Five — Interpret

Winner: cm, cm

Verify:

  • Diameter 6 cm < 12 cm ✓
  • Height 8.84 cm < 12 cm ✓
  • Volume cm³ ✓

⚠️ Math gives a solution. Interpret checks it's a good one.

Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 1 of 2

Check-In: Setting Up a Design Problem

A storage shed must:

  • Hold at least 10 m³
  • Fit through a gate that is 3 m wide
  • Use minimum material (minimize SA)

Identify:
a) Two constraints (as inequalities)
b) The objective (as a phrase or formula)

Think before advancing.

Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 1 of 2

Answer: Constraints and Objective for Shed

Constraints (Step 2):

Requirement Math
Volume at least 10 m³
Fits through 3 m gate m

Objective (Step 3):

Minimize surface area: SA = 2ℓw + 2ℓh + 2wh

Many valid constraint interpretations exist —
depth, height limits depend on what the design specifies.

Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 1 of 2

From Any Design to the Best Design

The modeling cycle finds valid designs.

Optimization finds the best design within constraints.

Key question: among all cylinders with volume 400 cm³,
which dimensions give the minimum surface area?

→ This is the classic can optimization problem

Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 1 of 2

Volume Constraint Reduces Two Variables to One

For a cylinder with fixed volume V = 400 cm³:

  • Choosing determines entirely
  • Two-variable problem collapses to one variable

This is why optimization is possible:
once you pick , everything else follows.

Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 1 of 2

Setting Up the Can Optimization Problem

Volume cm³ → constraint links and :

Cylinder showing top, bottom, and lateral surface

Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 1 of 2

Building the Can Optimization Table

(cm) (cm) SA (cm²) Cost (cents)
2 31.83 425 127
3 14.15 323 97
4 7.96 301 90
5 5.09 317 95
6 3.54 360 108

Minimum surface area near cm, cm

Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 1 of 2

The SA vs r Curve Shows the Minimum

Surface area vs radius graph for can with V=400 cm³, U-shaped curve with minimum near r=4

Minimum SA occurs at cm — the bottom of the U-curve.

Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 1 of 2

Optimal Cylinder Has Height Equal to Diameter

At the minimum, (height equals diameter):

Quantity Value
Optimal radius cm
Optimal height cm
Height/diameter ratio — true at the unconstrained minimum

This holds for any fixed volume — the optimal ratio is a geometric property, not specific to 400 cm³.

Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 1 of 2

Optimization Check-In: Working at r = 5

A can must hold 1000 cm³ of paint.

At cm:

a) What is ?
b) What is SA?

Set up and compute before advancing.

Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 1 of 2

Answer: Can Dimensions at r = 5 cm

Given: cm³, cm

Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 1 of 2

Box Optimization: Setting Up the Equations

Open-top square-base box, cm³. Minimize total SA.

Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 1 of 2

Box Optimization: Table Finds the Minimum

(cm) (cm) SA (cm²)
5 40.0 825
10 10.0 500
12 6.9 478
15 4.4 492

Minimum near cm — optimal height .

Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 1 of 2

Why Real Cans Differ from Optimal Cans

The mathematical optimum gives — but most soup cans are taller and thinner:

  • Shelf: tall cans fit more units per row
  • Label: more height = more branding space
  • Stacking: certain proportions are more stable

⚠️ The model doesn't include every constraint — always interpret.

Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 1 of 2

Key Takeaways from Deck One

Modeling cycle: Define → Constrain → Set Up → Explore → Interpret

Volume constraint → one variable; optimal cylinder

⚠️ Watch out:

  • Constraint (fixed) vs. objective (minimize) — always label both
  • Always interpret: does the solution make physical sense?
Grade 10 Geometry | HSG.MG.A.3
Geometric Methods for Design | Lesson 1 of 2

Preview: Constraint Design and Grid Systems

Deck 2 builds on today's modeling cycle:

  • Chunk 3: Constraint-based design — shipping boxes, water tanks, packaging efficiency
  • Chunk 4: Geometry in 2D design — typographic grids, golden ratio, page proportions

Design shapes not only containers but every page and screen.

Grade 10 Geometry | HSG.MG.A.3