Third Angle Is Determined Automatically
- △ABC: ∠A = 50°, ∠B = 60° → ∠C = 70°
- △DEF: ∠D = 50°, ∠E = 60° → ∠F = 70°
All three angle pairs match — even though we only specified two.
Quick Check: Third Angle Pairs
△PQR: ∠P = 40°, ∠Q = 80° → ∠R = ?
△STU: ∠S = 40°, ∠T = 80° → ∠U = ?
Do all three angle pairs match between these two triangles?
Calculate ∠R and ∠U before the next slide...
Two Angles → Three Match. What About Sides?
✓ Two angle pairs match → all three angle pairs match (angle sum theorem)
But: Similar triangles also need proportional sides.
? Equal angles → proportional sides automatically?
The AA Criterion says: YES — but we need to prove it.
AA Criterion: Statement and Scope
AA Criterion: If two angles of one triangle are congruent to two angles of another triangle, then the triangles are similar.
Formally: If ∠A ≅ ∠D and ∠B ≅ ∠E, then △ABC ~ △DEF.
Triangles only: AA works because of the triangle angle sum theorem. Equal angles alone do not guarantee similarity for quadrilaterals or other polygons.
Quick Check: Identifying AA
Which pairs can we confirm similar by AA?
Pair 1: △ABC with ∠A = 35°, ∠B = 80°
△DEF with ∠D = 35°, ∠E = 80°
Pair 2: △PQR with ∠P = 60°, ∠Q = 60°
△XYZ with ∠X = 60°, ∠Z = 60°
For Pair 2: are you matching corresponding angles?
Proof Strategy: Construct the Transformation
Recall: △ABC ~ △DEF means a similarity transformation maps △ABC onto △DEF.
Proof approach: Given ∠A ≅ ∠D and ∠B ≅ ∠E, construct the transformation.
Transformation sequence: Translate → Rotate → Dilate
If we build this successfully, similarity is proven by definition.
Proof Setup: Given and Goal
Given: △ABC and △DEF with ∠A ≅ ∠D and ∠B ≅ ∠E
To prove: △ABC ~ △DEF
Method: Build a transformation sequence in three steps:
- Translate △ABC so vertex A coincides with D
- Rotate the image so side A'B' aligns with ray DE
- Dilate from D to scale the triangle to match △DEF exactly
Step 1: Translate A to D
Translation: Move △ABC so A lands on D.
- Image: △A'B'C' with A' = D
- Rigid motion → all angles and distances preserved: ∠A' = ∠A, ∠B' = ∠B
Step 2: Rotate to Align Ray A'B' with Ray DE
Rotation: Rotate △A'B'C' around D so ray A'B' aligns with ray DE.
- Image: △A''B''C'' with ray A''B'' on ray DE
- Rigid motion preserves angles: ∠A'' = ∠A = ∠D and ∠B'' = ∠B = ∠E
After Rigid Motions: Current State
After translation and rotation:
- A'' = D (by construction)
- Ray A''B'' lies on ray DE (by construction)
- ∠A'' = ∠A = ∠D (rigid motions preserve angles + given ∠A = ∠D)
- ∠B'' = ∠B = ∠E (rigid motions preserve angles + given ∠B = ∠E)
What remains: the triangle is correctly positioned. Now adjust the size.
Quick Check: Why Rigid Motions Preserve Angles
Question: Why do translations and rotations preserve angle measures?
- A) They scale all distances proportionally
- B) They preserve all distances, so shapes — and angles — stay identical
- C) They only preserve distances along one axis
- D) Angles are independent of all distances
Think about what "rigid" means before selecting...
Angle Equality Forces Ray Alignment
After rigid motions, both rays start at D and make the same angle with ray DE:
- Ray A''C'' makes angle ∠A'' with ray DE
- Ray DF makes angle ∠D with ray DE
- Since ∠A'' = ∠D, these two rays are the same ray
Conclusion: Ray A''C'' lies along ray DF — the angle equality forces this.
Step 3: Dilate to Match Sizes
Dilation: Center D, scale factor
- B'' scales along ray DE → lands at E (distance DE from D)
- C'' scales along ray DF → lands at F
Dilation Result: Triangle Maps Exactly
After dilation from D with
- A'' → D (center of dilation stays fixed)
- B'' → E (scaled along ray DE to distance DE from D)
- C'' → F (scaled along ray DF to correct distance)
Result: △A''B''C'' maps exactly onto △DEF.
Proof Conclusion
Transformation sequence applied to △ABC:
- Translate (A → D)
- Rotate (ray A'B' → ray DE)
- Dilate from D with scale factor
This sequence is a similarity transformation (rigid motions + dilation).
Therefore: △ABC ~ △DEF ∎
AA is a proven theorem, not an observation.
Check-In: Explain the Proof Steps
Challenge: Explain what each step accomplishes and why it's possible.
- Why can we always translate A to D?
- Why can we always rotate to align ray A'B' with ray DE?
- Why does angle equality force ray A''C'' to lie on ray DF?
- Why does the dilation send B'' to E and C'' to F?
Try explaining steps 3 and 4 in particular — those carry the proof.
Worked Example: Scale Factor from the Proof
Given: △ABC with ∠A = 50°, ∠B = 60°; △DEF with ∠D = 50°, ∠E = 60°
Also: AB = 5, DE = 10
Step 1: Two angle pairs match → △ABC ~ △DEF by AA ✓
Step 2: Scale factor from the dilation step:
Result: Every side in △DEF is 2 × the corresponding side in △ABC.
AA as Theorem, Not Axiom
Why does the proof approach matter?
AA is derived from:
- The transformation definition of similarity (HSG.SRT.A.2)
- Properties of rigid motions (preserve angles and distances)
- Properties of dilations (scale distances from a center, preserve angles)
AA is not assumed — it is proved. This connects AA to the transformation framework you built in HSG.SRT.A.1 and A.2.
Key Takeaways: Understanding and Proof
✓ Two angles determine three — angle sum theorem makes the third automatic
✓ AA Criterion proven — translate + rotate + dilate maps any two triangles with equal angle pairs
✓ AA for triangles only — the angle sum constraint is what makes the proof work
Two angle pairs are enough — "AA" means exactly that, not "AAA"
AA proves similarity (same shape) — Deck 2 will show: not necessarily the same size
Next: Deck 2 — Applying the AA Criterion
Coming up in Deck 2:
- Apply AA efficiently: identify angle pairs → conclude similarity
- Three example contexts: direct angles, parallel lines, right triangles
- Distinguish AA (similarity) from ASA/AAS (congruence) — with a concrete counterexample
- Three real-world problems: shadows, map scaling, parallel segments
AA is your most efficient tool for identifying similar triangles. Let's use it.