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Surface Area of 3D Solids | Geometry & Trigonometry

Surface Area of 3D Solids

SAT Geometry and Trigonometry

In this lesson:

  • Calculate surface area of prisms and cylinders
  • Calculate surface area of pyramids, cones, and spheres
  • Solve applied problems on the SAT
Grade 10 SAT Math | Domain 4: Geometry and Trigonometry
Surface Area of 3D Solids | Geometry & Trigonometry

Your Learning Goals for This Lesson

By the end of this lesson, you will be able to:

  1. Calculate surface area of prisms and cylinders
  2. Calculate surface area of pyramids and cones
  3. Calculate the surface area of spheres
  4. Solve applied surface area problems in context
Grade 10 SAT Math | Domain 4: Geometry and Trigonometry
Surface Area of 3D Solids | Geometry & Trigonometry

You Already Know What You Need

You already know how to find areas of 2D shapes.

  • Rectangle:
  • Circle:
  • Triangle:

Surface area of a 3D solid is just adding up 2D areas — one face at a time.

Grade 10 SAT Math | Domain 4: Geometry and Trigonometry
Surface Area of 3D Solids | Geometry & Trigonometry

A Solid Unfolds Into a Net

Rectangular prism exploding into its six flat faces — net concept

Surface area = total area of all faces when the solid is unfolded flat

Grade 10 SAT Math | Domain 4: Geometry and Trigonometry
Surface Area of 3D Solids | Geometry & Trigonometry

Rectangular Prism: Three Pairs of Faces

Rectangular prism net: three labeled pairs of rectangles, each pair a different shade

Three pairs of congruent opposite faces: top/bottom, front/back, left/right

Grade 10 SAT Math | Domain 4: Geometry and Trigonometry
Surface Area of 3D Solids | Geometry & Trigonometry

Breaking Down the Prism SA Formula

  • = top and bottom faces
  • = front and back faces
  • = left and right faces

Find each pair, double it, and add.

Grade 10 SAT Math | Domain 4: Geometry and Trigonometry
Surface Area of 3D Solids | Geometry & Trigonometry

Example 1: Box with Whole Numbers

A box: , , cm. Find SA.

Top/bottom:

Front/back:

Left/right:

Grade 10 SAT Math | Domain 4: Geometry and Trigonometry
Surface Area of 3D Solids | Geometry & Trigonometry

Example 2: Box with Decimals

A box: 12.5 × 4.2 × 6.0 cm. Find SA.

Top/bottom:

Front/back:

Left/right:

Grade 10 SAT Math | Domain 4: Geometry and Trigonometry
Surface Area of 3D Solids | Geometry & Trigonometry

Quick Check: A Storage Cube Problem

A storage cube has side length 7 cm.

What is its surface area?

All six faces are identical — use what you know.

(Think before the next slide…)

Grade 10 SAT Math | Domain 4: Geometry and Trigonometry
Surface Area of 3D Solids | Geometry & Trigonometry

Cube Check: Walking Through the Solution

Side = 7 cm → all faces are 7 × 7 = 49 cm²

Or use the formula:

Grade 10 SAT Math | Domain 4: Geometry and Trigonometry
Surface Area of 3D Solids | Geometry & Trigonometry

Cylinder: Net is Two Circles + Rectangle

Cylinder net: two circles labeled πr², rectangle with width labeled 2πr and height labeled h

  • Two circular bases:
  • Lateral surface (rectangle): width = , height =
Grade 10 SAT Math | Domain 4: Geometry and Trigonometry
Surface Area of 3D Solids | Geometry & Trigonometry

The Cylinder Formula from the Net

  • = two circular bases
  • = lateral (curved) surface

SAT note: Problems may ask for lateral SA only — read carefully.

Grade 10 SAT Math | Domain 4: Geometry and Trigonometry
Surface Area of 3D Solids | Geometry & Trigonometry

Cylinder Example: Total and Lateral SA

A cylinder has cm and cm.

Total SA:

Lateral SA only:

Grade 10 SAT Math | Domain 4: Geometry and Trigonometry
Surface Area of 3D Solids | Geometry & Trigonometry

Check-In: Watch the Diameter Trap

A cylindrical can has diameter 6 cm and height 8 cm.

Find the total surface area. Leave your answer in terms of .

Step 1: What is the radius?

(Pause and solve — next slide shows the answer)

Grade 10 SAT Math | Domain 4: Geometry and Trigonometry
Surface Area of 3D Solids | Geometry & Trigonometry

Diameter Trap: Here Is the Answer

Step 1 always: If given diameter, write immediately.

Grade 10 SAT Math | Domain 4: Geometry and Trigonometry
Surface Area of 3D Solids | Geometry & Trigonometry

Pyramids and Cones: Slant Height

Cross-section of a pyramid/cone showing vertical height h, base radius/half-edge r, and slant height l forming a right triangle

  • = vertical height (straight up from center)
  • = slant height (along the face — what the formula needs)
  • by the Pythagorean theorem
Grade 10 SAT Math | Domain 4: Geometry and Trigonometry
Surface Area of 3D Solids | Geometry & Trigonometry

Pyramid Formula: Base Plus Lateral Faces

  • = area of the base
  • = perimeter of the base
  • = slant height (not vertical height)

For a square pyramid: and

Grade 10 SAT Math | Domain 4: Geometry and Trigonometry
Surface Area of 3D Solids | Geometry & Trigonometry

Square Pyramid: Base Edge Six Meters

A square pyramid has base edge m and slant height m.

Base:

Lateral:

Grade 10 SAT Math | Domain 4: Geometry and Trigonometry
Surface Area of 3D Solids | Geometry & Trigonometry

Cone: Find Slant Height from Vertical Height

A cone: cm, cm (vertical). Find total SA.

Step 1 — slant height:

Step 2 — apply formula:

Grade 10 SAT Math | Domain 4: Geometry and Trigonometry
Surface Area of 3D Solids | Geometry & Trigonometry

The Sphere: One Elegant Curved Surface

Sphere showing four great circles unwrapping — 4πr² intuition

The sphere's surface equals exactly four great circles.

Grade 10 SAT Math | Domain 4: Geometry and Trigonometry
Surface Area of 3D Solids | Geometry & Trigonometry

Sphere Example: Diameter Given Again

A sphere has diameter 10 in. Find the surface area.

Grade 10 SAT Math | Domain 4: Geometry and Trigonometry
Surface Area of 3D Solids | Geometry & Trigonometry

Applied Problem 1: Painting a Tank

A cylindrical water tank has m and m. Paint covers only the curved side (no top or bottom). How many square meters need painting?

Only the lateral surface — bases are excluded.

Grade 10 SAT Math | Domain 4: Geometry and Trigonometry
Surface Area of 3D Solids | Geometry & Trigonometry

Applied Problem 2: Wrapping a Gift Box

A box is 30 cm × 20 cm × 10 cm. How much wrapping paper is needed (no overlap)?

Total surface area — all six faces.

Grade 10 SAT Math | Domain 4: Geometry and Trigonometry
Surface Area of 3D Solids | Geometry & Trigonometry

Applied Problem 3: Material Cost

A metal cone (no base) has cm and cm. Metal costs $0.50 per cm².

Lateral SA (no base):

Cost:

Grade 10 SAT Math | Domain 4: Geometry and Trigonometry
Surface Area of 3D Solids | Geometry & Trigonometry

Key Takeaways and SAT Watch-Outs

⚠️ Slant height — use , not , in formulas
⚠️ Diameter — halve it first:
⚠️ Lateral vs. total SA — read the question twice
⚠️ Sphere vs. volume for SA, for volume
⚠️ Units — SA is always in cm², m², in²

Grade 10 SAT Math | Domain 4: Geometry and Trigonometry
Surface Area of 3D Solids | Geometry & Trigonometry

What Comes Next: Volume of Solids

Next lesson: Volume of 3D Solids

  • Same five solid types, formulas on the SAT reference sheet
  • SA vs. volume — often paired in the same SAT problem

Surface area = the outside. Volume = what's inside.

Grade 10 SAT Math | Domain 4: Geometry and Trigonometry